Post a New Question
posted by Julie on Tuesday, November 27, 2012 at 8:14pm.
how would you prepare 250 mL of a .1 M C12H22O11 starting with 2.5M C12H22O11
I would use the dilution formula of c1v1 = c2v2. c = concn v = volume Plug in the numbers.
More Related Questions