Calculate the maximum mass of calcium metal that should be used in an equivalent mass determination, with a 100 ml gas measuring tube for collection. Assume 80 ml of hydrogen gas at standard conditions for the purposes of calculation.

80 mL x (1 mol/22,400 mL) = 0.00357 mols H2 gas.

Ca + 2H2O ==> H2 + Ca(OH)2
mols H2 gas = mols Ca.
g Ca = mols Ca x atomic mass Ca.

I made no correction for collection over water since that was not mentioned.

To calculate the maximum mass of calcium metal that should be used in an equivalent mass determination, we need to consider the stoichiometry of the reaction and the molar volume of hydrogen gas at standard conditions.

1. Write the balanced chemical equation for the reaction:
Calcium (Ca) + Hydrochloric Acid (HCl) → Calcium Chloride (CaCl2) + Hydrogen Gas (H2)

2. Determine the stoichiometry of the reaction:
From the balanced equation, we can see that 1 mole of calcium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

3. Calculate the molar volume of hydrogen gas at standard conditions:
The molar volume of any gas at standard conditions is 22.4 liters per mole.

4. Convert the given volume of hydrogen gas to liters:
80 ml = 0.08 liters

5. Use the molar volume of hydrogen gas to calculate the number of moles of hydrogen gas:
0.08 liters × (1 mole / 22.4 liters) = 0.00357 moles

6. Since the stoichiometry of the reaction is 1:1 between calcium and hydrogen gas, the number of moles of calcium is also 0.00357 moles.

7. Calculate the molar mass of calcium (Ca):
The molar mass of calcium is 40.08 g/mol.

8. Calculate the maximum mass of calcium metal:
0.00357 moles × 40.08 g/mol = 0.1429 grams

Therefore, the maximum mass of calcium metal that should be used in the equivalent mass determination is approximately 0.143 grams.

To calculate the maximum mass of calcium metal that should be used in an equivalent mass determination, we need to consider the volume of hydrogen gas collected and its molar volume at standard conditions.

1. Convert the volume of the gas collected to liters:
Volume = 100 ml = 100/1000 = 0.1 L

2. Use Avogadro's Law to find the number of moles of hydrogen gas collected:
V = n * Vm
Where:
V is the volume of gas in liters,
n is the number of moles,
Vm is the molar volume of the gas at standard conditions (22.4 L/mol for hydrogen gas)

n = V / Vm
n = 0.1 L / 22.4 L/mol = 0.00446 mol

3. Calcium reacts with hydrogen gas in a 1:1 molar ratio.
This means that for every mole of calcium, we will produce one mole of hydrogen gas.

Therefore, the maximum mass of calcium that should be used can be calculated using the molar mass of calcium:
Molar mass of calcium = 40.08 g/mol

Mass = n * molar mass
Mass = 0.00446 mol * 40.08 g/mol = 0.178 g

So, the maximum mass of calcium metal that should be used in this equivalent mass determination is 0.178 grams.