Wednesday

January 28, 2015

January 28, 2015

Posted by **Ama** on Tuesday, November 27, 2012 at 3:33pm.

tan θ = - root of 3/3

- precalculus -
**Reiny**, Tuesday, November 27, 2012 at 5:03pmtan Ø = -√3/3

so Ø must be in quadrants II or IV

angle in standard position = 30° ( take tan^-1 (+√3/3) )

so Ø = 180-30 = 150° or Ø = 360-30 = 330°

since the period of the tangent curve is 180°

the general solution is

150° + 180k°

or in radians:

5π/6 + πk

**Answer this Question**

**Related Questions**

precalculus - Solve the given equation. (Enter your answers as a comma-separated...

precalculus - Find all solutions of the given equation. (Enter your answers as a...

precal - Solve the given equation. (Enter your answers as a comma-separated list...

precal - Solve the given equation. (Enter your answers as a comma-separated list...

calculus - Solve the given equation. (Enter your answers as a comma-separated ...

precal - Find all solutions of the given equation. (Enter your answers as a ...

precal - Solve the given equation. (Enter your answers as a comma-separated list...

precalculus - Use a Double- or Half-Angle Formula to solve the equation in the ...

precalculus - Solve the given equation. (Enter your answers as a comma-separated...

pre-calc help - Solve the given equation. (Enter your answers as a comma-...