a chemistry handbook lists the solubility of NaI as 184 per 100mL of H2O at 25 degrees Celcius.

1) How many moles of NaI can be dissolved in 100mL of H2O at 25 degrees Celcius?
2) What would be the molarity of a saturated aqueous solution of NaI prepared at 25 degrees Celcius , assuming that the added NaI does not add significantly to the volume of the H2O?

To answer these questions, we need to use the given solubility of NaI as 184 g/100mL of H2O.

1) How many moles of NaI can be dissolved in 100mL of H2O at 25 degrees Celcius?

To find the number of moles, we need to convert the mass of NaI to moles using its molar mass. The molar mass of NaI (sodium iodide) is 149.89 g/mol.

Mass of NaI = solubility of NaI * volume of water
= 184 g/100mL * 100mL
= 184 g

Number of moles of NaI = Mass of NaI / Molar mass of NaI
= 184 g / 149.89 g/mol
≈ 1.23 moles

Therefore, about 1.23 moles of NaI can be dissolved in 100mL of H2O at 25 degrees Celsius.

2) What would be the molarity of a saturated aqueous solution of NaI prepared at 25 degrees Celcius, assuming that the added NaI does not add significantly to the volume of the H2O?

Molarity (M) is the number of moles of solute per liter of solution. Since we have the moles of NaI from the previous calculation, we can calculate the molarity.

Volume of solution = volume of water = 100 mL = 0.1 L

Molarity = moles of NaI / volume of solution
= 1.23 moles / 0.1 L
= 12.3 M

Therefore, the molarity of a saturated aqueous solution of NaI prepared at 25 degrees Celsius, assuming that the added NaI does not add significantly to the volume of the H2O, would be approximately 12.3 M.

To answer these questions, we need to use the given information about solubility and basic chemistry concepts.

1) To find the number of moles of NaI that can be dissolved in 100 mL of water (H2O) at 25 degrees Celsius, we can use the formula:

Moles = Mass / Molecular Weight

First, we need to convert the given solubility value of NaI from grams per 100 mL to grams per mL. The solubility of NaI is 184 grams per 100 mL, so it is 1.84 grams per mL (since 100 mL / 100 = 1 mL).

Next, we find the molecular weight of NaI. Sodium (Na) has a molar mass of 22.99 grams/mole, and iodine (I) has a molar mass of 126.90 grams/mole. Adding these values together, we get the molecular weight of NaI as 149.89 grams/mole.

Now, we can calculate the number of moles using the formula:

Moles = Mass / Molecular Weight
Moles = 1.84 grams / 149.89 grams/mole

Calculating this, we find:
Moles = 0.012283 moles

Therefore, the number of moles of NaI that can be dissolved in 100 mL of water at 25 degrees Celsius is approximately 0.0123 moles.

2) To find the molarity of a saturated aqueous solution of NaI at 25 degrees Celsius, we need to calculate the concentration in moles per liter (mol/L) or Molarity. However, we should note that the added NaI does not significantly increase the volume of water.

Since we have calculated that 0.0123 moles of NaI dissolves in 100 mL of water, the final volume of the solution is 100 mL. However, we need to convert this to liters in order to calculate molarity.

Volume (in liters) = Volume (in milliliters) / 1000
Volume (in liters) = 100 mL / 1000
Volume (in liters) = 0.1 L

Now, we can calculate the molarity using the formula:

Molarity = Moles / Volume (in liters)
Molarity = 0.0123 moles / 0.1 L

Calculating this, we find:
Molarity = 0.123 M

Therefore, the molarity of a saturated aqueous solution of NaI prepared at 25 degrees Celsius, assuming that the added NaI does not add significantly to the volume of water, is approximately 0.123 M.

184 what? grams?

a. mols NaI = grams NaI/molar mass NaI.
b. M = mols NaI/L soln. You're assume that is 100 mL or 0.100 L.