posted by vince11 on .
Describe in detail by words how to prepare 200ml of .150M HCl from a 1.00 M HCl stock solution? Need help with this please?
i used C1V1=C2V2 and got volume 2 = 33L or 0.33mL.
to prepare the solution i need to weigh 1 gram of HCL (from 1.00M HCl stock solution)lets say i put it in a graduated cylinder, then i put the right amount of stock solution or water i'm confused until it reach the mark .33mL. pls pls check my answer thank you
Thanks for providing the numbers. I don't know what you did wrong but here is how you do it. Pay particular attention to the "how to do it" after you obtain the right number.
c1v1 = c2v2
200mL x 0.15M = 1.00M x v2
v2 = (200 x 0.15/1) = 30 mL.
Take 30.0 mL of the 1.00 M stock solution, place in a 200 mL volumetric flask (we'll assume they make such things), and add water to the mark.
You're working with volume; therefore, weighing is not the right word to use. Also, note that your 33 L (that isn't right) but it is converted to mL correctly either. 33 L = 33,000 mL and you should have thought something was wrong since you started out making 200 mL TOTAL volume.