0.2688 of a monoprotic acid neutralizes 16.4mL 0f 0.08133 M KOH. Calculate the molar mass of the acid in units of g/mol
chemistry - DrBob222, Tuesday, November 27, 2012 at 10:32pm
0.2688 what? grams?
HA + KOH ==> KA + H2O
mols KOH = M x L = ?
mols HA = mols KOH (look at the coefficients in the balanced equation.)
mols = grams/molar mass. You know mols and grams, solve for molar mass.