what volume of 14.8M ammonia is required for preparation of 3.1g of [cu(nh3)4]so4.h2o

mols [Cu(NH3)4]SO4.H2O = grams/molar mass.

You need 4x that number mols NH3. Do you know why?
M NH3 = mols NH3/L NH3. You know mols and M solve for L and convert to mL (the problem doesn't tell you the unit for volume).