How much heat is required to raise the temperature of a 35.0g block of aluminium from 125 degrees celcius to 322 degrees celcius?
Note the correct spelling of celsius.
q = mass Al x specific heat Al x (Tfinal-Tinitial) = ?
To determine the amount of heat required to raise the temperature of a substance, you need to use the equation:
Q = m * c * ΔT
Where:
- Q represents the amount of heat (in Joules)
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in J/g°C)
- ΔT is the change in temperature (in °C)
In this case, you are given:
- Mass (m) of the aluminum block: 35.0g
- Initial temperature (T1) of the aluminum block: 125°C
- Final temperature (T2) of the aluminum block: 322°C
The specific heat capacity (c) of aluminum is approximately 0.903 J/g°C.
Now, you can plug the values into the equation:
Q = 35.0g * 0.903 J/g°C * (322°C - 125°C)
Calculating the difference in temperature:
ΔT = 322°C - 125°C
ΔT = 197°C
Now, substituting the values back into the equation:
Q = 35.0g * 0.903 J/g°C * 197°C
Calculate the result:
Q = 6264.405 J
Therefore, approximately 6264.4 Joules of heat are required to raise the temperature of the 35.0g block of aluminum from 125°C to 322°C.