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November 28, 2014

November 28, 2014

Posted by **mandeep** on Tuesday, November 27, 2012 at 7:30am.

Find the probability that the committee will have at least one man.

- Probability-plse -
**Reiny**, Tuesday, November 27, 2012 at 9:23amtotal number of choices

= C(4,2) = 6

number of ways to pick 2 women

= C(2,2) = 1

number of ways with at least 1 man

= 1 - 1/6

= 5/6

Proof:

let the women be A, and B

let the men be C and D

choices

AB AC AD

BC BD

CD

of those 5 cases contain A or B

only one does not contain either an A or a B

My answer is correct

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