Posted by mandeep on Tuesday, November 27, 2012 at 7:30am.
A committee of two persons is selected from two men and two women.
Find the probability that the committee will have at least one man.

Probabilityplse  Reiny, Tuesday, November 27, 2012 at 9:23am
total number of choices
= C(4,2) = 6
number of ways to pick 2 women
= C(2,2) = 1
number of ways with at least 1 man
= 1  1/6
= 5/6
Proof:
let the women be A, and B
let the men be C and D
choices
AB AC AD
BC BD
CD
of those 5 cases contain A or B
only one does not contain either an A or a B
My answer is correct
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