Sara has twice as much money as Miguel. If she had $6 more. She would have 4/3 as much money as he has. How much money does each have now?

can't happen. How could she have less than twice as much if she had $6 more?

Check the problem.

I solved the problem like that:

Sara: 2x
Miguel: x

2x+6 =4/3x

18/3 =4/3 -6/3x

6 = -2/3x
x = - 9

so Miguel = -9

Sara = -18

Is it correct?

you know anybody with a negative age?

If you solved the equation your answer would be x(Miguel)=-9 and Sara=-18. There is no solution because you can't have a negative amount of money.

To solve this problem, we can use algebraic equations.

Let's assume that Miguel has M dollars. According to the given information, Sara has twice as much money as Miguel, so Sara would have 2M dollars.

The problem states that if Sara had $6 more, she would have 4/3 as much money as Miguel. This means that her new amount of money would be (2M + 6), and this would equal 4/3 of Miguel's amount (4/3 * M).

Now we can set up an equation to solve for the value of M:

2M + 6 = (4/3)M

To simplify this equation, we can multiply both sides by 3 to get rid of the fraction:

6M + 18 = 4M

Now, subtract 4M from both sides:

6M - 4M + 18 = 0

Simplifying further:

2M + 18 = 0

Subtracting 18 from both sides:

2M = -18

Finally, dividing both sides by 2:

M = -9

Since negative money doesn't make sense in this context, we have obtained an inconsistent result. Therefore, it seems that there was an error in the problem formulation or numerical values provided.