Posted by abraham on .
Find three consecutive integers such that the square of the third minus the first is equal to 2 more than 5 times the second.

math 
PsyDAG,
If they are consecutive, then one = x, the second = x+1 and the third = x+2.
(x2)^2  x = 5(x+1) + 2
I'll let you do the calculations.