Posted by **Disha** on Monday, November 26, 2012 at 11:52pm.

if the distance covered by an object in time is given by s(t)=t^2+5t where s(t) is in metersand t is in seconds, what is the distance covered in the interveral between 1 second and 5 seconds?

- calculus -
**Steve**, Monday, November 26, 2012 at 11:52pm
s(5)-s(1)

- calculus -
**Disha**, Monday, November 26, 2012 at 11:53pm
A 24 meters

B 30

C 40

D 42

E 44

- calculus -
**Disha**, Monday, November 26, 2012 at 11:54pm
so what would be the answer

- calculus -
**Steve**, Monday, November 26, 2012 at 11:57pm
plug in t=5 and t=1. subtract one from the other. what do you get? you've posted a lot of similar problems. By now you should be getting the hang of them.

- calculus -
**Disha**, Monday, November 26, 2012 at 11:59pm
30 ahh i get it now thanks

- calculus -
**Steve**, Tuesday, November 27, 2012 at 12:01am
ummm. what did you do?

s(5) = 5^2 + 5*5 = 50

s(1) = 1^1 + 5*1 = 6

s(5)-s(1) = 44, not 30

- calculus -
**disha**, Tuesday, November 27, 2012 at 12:07am
i did it like this

5^2=25 + 5^1= 5 = 30

i guess i did it wrong

- calculus -
**Steve**, Tuesday, November 27, 2012 at 12:11am
that's 5t. not 5^t

5*5 = 25

you did it wrong in two ways. you tried to do 5^2 + 1^2 but did 5^2 + 5^1 instead.

You did not include both terms in your evaluations.

*sigh* review your algebra, if you want to do well in calculus.

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