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December 18, 2014

December 18, 2014

Posted by **Sierra** on Monday, November 26, 2012 at 11:43pm.

*note my teacher has not taught me anything to do with w = 2pi/T as some help websites have used this route to find the answer, obviously there's another way that my teacher has taught us how to solve this kind of problem and i already know the answer is 0.89g i just don't know how to get there. Thanks.

- Physics Please Help ASAP -
**drwls**, Tuesday, November 27, 2012 at 12:28amUse the fact that the radius of the Earth is R = 6378 km.

At an altitude of 390 km, the shuttle is R = 6378+390 = 6768 km from the center of the earth. Centripetal a equals gravity g', which is proportional to 1/R^2. Therefore at 6768 km,

g' = g*(6368/6758)^2 = 0.8879 g

- Physics Please Help ASAP -
**Sierra**, Tuesday, November 27, 2012 at 12:48amthank you so much! super helpful i didn't realize i was overlooking the radius of earth!

- Physics Please Help ASAP -
**drwls**, Tuesday, November 27, 2012 at 5:53amYou're welcome. There are other ways to come up with the same answer using the universal G and the period of the satellite orbit, but this method is quicker.

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