Posted by Disha on Monday, November 26, 2012 at 10:54pm.
What is the value of this limit?
calculus - Disha, Monday, November 26, 2012 at 11:15pm
calculus - Reiny, Monday, November 26, 2012 at 11:48pm
lim (x^2 + 4)/(x^2 - 3x + 1)
x ---> 4
the first step in any limit is to actually sub in the approach value
in this case we get
lim(16+4)/(16 - 12 + 1)
= 4 , which is a real number, so we have no problem with this limit
the answer is 4 , all done!
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