A 1500kg car is approaching the hill shown in the figure at 15.0 m/s when it suddenly runs out of gas.

Part A

What is the car's speed after coasting down the other side?

without more info, ...

300

15?

The work you showed was really helpful. It's crazy how people can solve these types of equations without showing any work. Physics is a great course.

To find the car's speed after coasting down the other side of the hill, we need to consider the conservation of mechanical energy.

When the car reaches the top of the hill, it has potential energy due to its position and kinetic energy due to its motion. As it rolls down the hill, it converts some of the potential energy to kinetic energy.

Initially, the car has potential energy given by the formula:

PE = mgh

Where:
m = mass of the car (1500 kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height of the hill

Since the car runs out of gas at the top of the hill, no external force is acting on it. Therefore, mechanical energy is conserved, and the initial potential energy is equal to the kinetic energy at the bottom of the hill.

At the bottom of the hill, the car only has kinetic energy, which can be given by the formula:

KE = (1/2)mv^2

Where:
m = mass of the car (1500 kg)
v = final velocity of the car after coasting down the hill (to be determined)

Since the initial potential energy (PE) is equal to the final kinetic energy (KE), we can set up the equation:

PE = KE

mgh = (1/2)mv^2

Canceling out the mass:

gh = (1/2)v^2

Plugging in the given values:
g = 9.8 m/s^2
h = height of the hill (not provided)

At this point, we need more information about the height of the hill to calculate the final velocity of the car after coasting down the other side. Please provide the height or any other relevant information to proceed with the calculation.