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March 6, 2015

March 6, 2015

Posted by **Sally** on Monday, November 26, 2012 at 4:24pm.

(a) Calculate the new temperature Tf of the gas.______J

(b) Calculate the work done on the gas during the expansion.________kJ

- Physics -
**Elena**, Monday, November 26, 2012 at 5:53pm(a)

Ti=273+7.4=280.4 K

Vi/Ti = Vf/Tf

Vi/280.4 =8 Vi/Tf

Tf=8•280.4 = 2243.2 K

b) p•ΔV=νRΔT

ν =1 mol

p•ΔV= RΔT

W = p•ΔV= RΔT=

= 8.31•(2243.2-280.4)=

=1.63•10⁴ J =16.3 kJ

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