posted by please help on .
When a driver brakes an automobile, the friction between the brake drums and the brake shoes converts the car's kinetic energy to thermal energy. If a 1750-kg automobile traveling at 28 m/s comes to a halt, how much does the temperature rise in each of the four 8.0 kg iron brake drums? (The specific heat of iron is 448 J/kg · °C.)
ΔT = Mv²/8mc=1750•28²/8•8•448=47.9℃