Posted by chrissy on Monday, November 26, 2012 at 1:53pm.
f' = 1 + cos(x)
f'=0 when cos(x) = -1, or x=pi
however,
f''(x) = -sin(x) which is also 0 at x=pi.
So, (pi,pi) is an inflection point, not a max or min.
f(2pi) = 2pi
so that is the absolute max on [0,2pi]
Note that f'(x) >= 0 for all x, so there is no max or min, which require changing direction.
Related Questions
Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...
Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...
calc - let f(x)= -x^2 +3x on the interval [1,3] . Find the absolute maximum and ...
calc - Let g(s)=1/(s-2)on the interval (0,1). Find the absolute maximum and ...
Calculus - Find the absolute maximum and absolute minimum values of f(x)=sinx...
Calculus - Find the absolute maximum & minimum of the function f (x)=e^x for...
Calculus - The function f(x)=(x^4)-(10x^3)+(18x^2)-8 is continuous on the closed...
Math - Find the absolute extrema of the function on the closed interval. f (x...
Jessica - Find absolute maximum and minimum for f(x)=(3x^3)−(18x^2)+...
Calculus - maximum and minimum of y = cos(x) + sin (x)on the interval [0,2pi]
For Further Reading
