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November 22, 2014

November 22, 2014

Posted by **luca** on Monday, November 26, 2012 at 1:50pm.

y = 2x + 1, y = 13 − x^2, x = −1, x = 2

- calc -
**Steve**, Monday, November 26, 2012 at 2:39pmsince y is a function of x in both cases, it will be easier to integrate along x.

∫[-1,2] (13-x^2) - (2x+1) dx

integrating along y would require breaking the area into two parts.

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