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A 1.0 102 g piece of copper at a temperature of 460 K and a 2.0 102 g piece of aluminum at a temperature of 2.2 102 K are dropped into an insulated bucket containing 5.0 102 g of water at 280 K. What is the equilibrium temperature of the mixture? (Use the specific heats found in this table.)


I have 252.2tf=57692
tf=228 K

Based off of the table the specific heats for Aluminum and Copper are. Al-0.900 and Copper-0.215

  • Physics - ,

    And the answer that I have is wrong

  • Physics - ,

    I'm sorry for Aluminum its 0.215 and for Copper its 0.0922

  • Physics - ,

    The grams for Aluminum are 2.0e2 and the temperature for Aluminum is 2.2e2. The grams for water is 5.0e2.

  • Physics - ,

    Cu: m₁=0.1 kg, c₁=385 J/kg•K, T₁=460 K,
    Al: m₂=0.2 kg, c₂=930 J/kg•K, T₂=220 K,
    Water: m₃=0.5 kg, c₃=4183 J/kg•K, T₃280 K.
    T=?
    m₁c₁(T₁-T) = m₂c₂(T-T₂) +m₃c₃(T-T₃)
    T= (m₁c₁T₁ + m₂c₂T₂ + m₃c₃T₃)/(m₁c₁ + m₂c₂ + m₃c₃)=
    ...=278.1 K

  • Physics - ,

    woah!

  • Physics - ,

    Thank you Elena!

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