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November 27, 2014

November 27, 2014

Posted by **Sue** on Monday, November 26, 2012 at 8:53am.

- algebra -
**kay**, Monday, November 26, 2012 at 10:46amLet Adam=x, Cynthia=y and Fred=z

We have: x=3y, z=x-16 , x-1=2(y-1+z-1)

so x=3y, x=z+16 and x=2y+2z-3

3y=z+16 so z=3y-16

Also,

3y=2y+2z-3 so y=2z-3 = 2(3y-16)-3=6y-35 so 5y=35 and y=7, z=3(7)-16=5 and x=3(7)=21

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