Two blocks, (Mass of block 1 = 2.3kg, Mass of block 2 = 1.2kg), are in contact on a frictionless table. If a horizontal force of 3.2N is applied to the larger block, what is the acceleration of the smaller block. Describe all external forces that are acting on the two blocks

To find the acceleration of the smaller block, we need to first understand the external forces acting on the two blocks.

1. Normal Force: The table exerts an upward normal force on both blocks, preventing them from falling through the table. Since the table is frictionless, the normal force magnitude is equal to the weight of each block.

2. Weight: Both blocks are subject to the force of gravity, which is pulling them downward. The weight of a block is calculated by multiplying its mass by the gravitational acceleration (9.8 m/s^2).

Now, let's consider the applied force on the larger block. This force creates a net force on the entire system, which causes the blocks to accelerate.

Using Newton's second law of motion (F = ma), we can write the following equation for the larger block:

F_applied - F_friction = m1 * a

Where:
F_applied is the applied force (3.2 N)
F_friction is the frictional force between the blocks (zero, since the table is frictionless)
m1 is the mass of the larger block (2.3 kg)
a is the acceleration of the blocks

Since F_friction is zero, the equation simplifies to:

F_applied = m1 * a

Solving for a:

a = F_applied / m1

a = 3.2 N / 2.3 kg

Calculating the value:

a ≈ 1.39 m/s^2

Therefore, the acceleration of the smaller block is approximately 1.39 m/s^2.