Posted by Olivia on Sunday, November 25, 2012 at 8:47pm.
Set f'=0
x=0,-2,5 for f' to be zero.
maximum is when f" is negative
a) f"=(x+2)(x-5)+x(x-5)+(x(x+2)
at x=0, f"=-10 so x=0 is max
b. f" at x=-2
f"=(0+ -2(-7) = positive, so at x=-2, it is minimum
c. f" at x=5
f"=0+0+35 positive, local maximum
check my calcs
oops, when f" is 35, local min
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