Physics
posted by Minte on .
An object moving with uniform acceleration has a velocity of 12m/s in the +ve xdirection,when its xcoordinate 3cm.if its xcoordinate 2sec. later is 5cm ,what is the acceleration?

d=vi(t)+1/2 a t^2
8=12*2+1/2 a (4)
solve for a 
16cm/s^2