# college algebra--I really need help!!

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solve the following exponential equation. exact answers only.

1-9x 2x
2 = e

I hope that you understand this question. I don't and need some help please. Can you show all answers please.

• college algebra--I really need help!! -

Um....where does 1-9x and 2x connect? Are they just separate algebraic expressions? And where does e come into play? Thanks

• college algebra--I really need help!! -

Ok, it didn't turn out right. This is the question.

2 with the 1-9x above the 2 = e with 2x above the e.

Hope this makes more sense now and you can help me and show me how you came about getting the answers.

Thanks!!!!

• college algebra--I really need help!! -

2^(1-9x) = e^2x ??? is that what you mean?

if so then

ln (e^2x) = 2x ln e = 2x
and
ln [ 2^(1-9x) ] = (1-9x) ln 2 = .693(1-9x)

so
2x = .693 (1-9x)
2x = .693 - 6.24 x
8.24 x = .693
x = .0841

• college algebra--I really need help!! -

Yes, thanks. I am not quite sure how to make some of the signs when posting my questions here. I am probably older than most and really trying to learn to post them right. Is there a place that you might can refer me to, so that I can try and learn the right signs and symbols????