a sodium hydroxide solution was prepared according to the procedure outlined in this weeks experiment. This sodium hydroxide solution was standardized by by titration against exactly 10mL of a 0.28M hydrochloric acid solution. In three titrations, the volumes of the sodium hydroxide solution required to reach the equivalence point where 8.03 mL, 8.18mL, and 7.94mL. What is the molarity of your sodium hydroxide solution

NaOH + HCl ==> NaCl + H2O

mols HCl = M x L = ?
mols NaOH = mols HCl (Look at the coefficients in the balanced equation.)
Then M NaOH = molos NaOH/L NaOH.
You may calculate the three values for the three different volumes, then average the three M values OR you may average the three volumes initially and make one calculation.

To determine the molarity of the sodium hydroxide (NaOH) solution, you need to use the data from the titrations.

The equation for the neutralization reaction between NaOH and HCl is:
NaOH + HCl -> NaCl + H2O

Given that the volume of HCl solution used in each titration is 10 mL and the molarity of HCl is 0.28 M, we can calculate the number of moles of HCl used in each titration as follows:

moles of HCl = volume (in L) x molarity

moles of HCl = 0.01 L x 0.28 mol/L

moles of HCl = 0.0028 mol

Since the balanced equation shows a 1:1 ratio between NaOH and HCl, the same number of moles of NaOH is used in the neutralization reaction. Therefore, to find the molarity of NaOH, we need to divide the moles of NaOH by the volume of NaOH used in each titration.

Molarity of NaOH = moles of NaOH / volume (in L) of NaOH

Calculating the molarity for each titration:

1) Molarity of NaOH = 0.0028 mol / 0.00803 L = 0.348 M
2) Molarity of NaOH = 0.0028 mol / 0.00818 L = 0.342 M
3) Molarity of NaOH = 0.0028 mol / 0.00794 L = 0.352 M

To find the average molarity of NaOH, you can add up the individual molarities and divide by the number of titrations:

Average Molarity of NaOH = (0.348 M + 0.342 M + 0.352 M) / 3

Average Molarity of NaOH = 0.347 M

Therefore, the molarity of the sodium hydroxide solution is approximately 0.347 M.