sodium oxide reacts with carbon dioxide to form sodium carbonate. How much carbon dioxide is needed to produce 79g or sodium carbonate?
first you must find the # of moles of NaCO3 produced:
79g NaCO3/83g(per mole of NaCO3)NaCO3 = .95 moles NaCO3
then you compare the # of moles in the equation, its a 1:1 molar ratio
NaO + CO2 ==> NaCO3
(use dimensional analysis)
.95 mol NaCO3| 1 mol NaO | 39g NaO
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| 1 mol NaCO3 | 1 mol NaO
you multiply across the top and divide the by the bottom. get rid of the units that repeat on the top and bottom and you're left with grams of NaO
37g NaO needed.
Na2O + CO2 ==> Na2CO3
The molar mass of Na2CO3 is 106.
To find out how much carbon dioxide is needed to produce 79g of sodium carbonate, we need to use the balanced chemical equation for the reaction.
The balanced equation for the reaction between sodium oxide (Na₂O) and carbon dioxide (CO₂) to form sodium carbonate (Na₂CO₃) is:
Na₂O + CO₂ → Na₂CO₃
From the balanced equation, we can see that the molar ratio between Na₂O and CO₂ is 1:1. This means that 1 mole of Na₂O reacts with 1 mole of CO₂.
The molar mass of Na₂O is 61.98 g/mol, and the molar mass of Na₂CO₃ is 105.99 g/mol.
To find the amount of CO₂ needed to produce 79g of Na₂CO₃, we need to convert the given mass into moles and then use the molar ratio from the balanced equation.
First, we calculate the number of moles of Na₂CO₃:
Moles of Na₂CO₃ = mass / molar mass
Moles of Na₂CO₃ = 79g / 105.99 g/mol
Moles of Na₂CO₃ ≈ 0.746 mol
Since the molar ratio between Na₂O and CO₂ is 1:1, the number of moles of CO₂ required will be the same as the number of moles of Na₂CO₃:
Moles of CO₂ = Moles of Na₂CO₃ ≈ 0.746 mol
Finally, we can calculate the mass of CO₂ needed using its molar mass:
Mass of CO₂ = Moles of CO₂ × molar mass
Mass of CO₂ = 0.746 mol × 44.01 g/mol
Mass of CO₂ ≈ 32.8 g
Therefore, approximately 32.8 grams of carbon dioxide is needed to produce 79 grams of sodium carbonate.
To determine the amount of carbon dioxide required to produce 79g of sodium carbonate, we need to consider the balanced chemical equation for the reaction between sodium oxide (Na2O) and carbon dioxide (CO2):
Na2O + CO2 -> Na2CO3
From the equation, we can see that 1 mole of Na2O reacts with 1 mole of CO2 to produce 1 mole of Na2CO3. To calculate the amount of CO2 required, we need to convert the given mass of Na2CO3 (79g) into moles.
Step 1: Find the molar mass of Na2CO3:
Na = 22.99 g/mol (sodium atomic mass from the periodic table)
C = 12.01 g/mol (carbon atomic mass)
O = 16.00 g/mol (oxygen atomic mass)
Molar mass of Na2CO3:
2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 105.99 g/mol
Step 2: Calculate the number of moles of Na2CO3:
Number of moles = Mass / Molar mass
Number of moles = 79g / 105.99 g/mol = 0.745 mole
Step 3: The balanced equation tells us that the mole ratio between Na2CO3 and CO2 is 1:1. Therefore, the amount of CO2 required is also 0.745 mole.
Finally, to convert moles of carbon dioxide (CO2) to grams, we can multiply by the molar mass of CO2:
Molar mass of CO2 = 12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol
Mass of CO2 required = Number of moles of CO2 * Molar mass of CO2
Mass of CO2 required = 0.745 mole * 44.01 g/mol = 32.76 g
Therefore, approximately 32.76 grams of carbon dioxide are needed to produce 79 grams of sodium carbonate.