How many moles of vanadium atoms, V, are needed to combine with 0.725 mol of O atoms to make vanadium pentoxide,V2O5?

4V + 5O2 ==> 2V2O5

0.725 mol O x (4 mols V/10 mols O) = ?

4.34 How many moles of vanadium atoms, V, are needed to combine with 0.565 mol of O atoms to make vanadium pentoxide, V,0,?

To determine the number of moles of vanadium atoms needed to combine with 0.725 mol of oxygen atoms to form vanadium pentoxide (V2O5), we first need to understand the stoichiometry of the reaction.

The balanced chemical equation for the formation of V2O5 is:

4 V + 5 O2 → 2 V2O5

From the equation, we can see that 4 moles of vanadium (V) react with 5 moles of oxygen (O2) to produce 2 moles of vanadium pentoxide (V2O5).

Given that we have 0.725 mol of oxygen atoms, we can set up a proportion to find the corresponding number of moles of vanadium atoms:

(4 mol V / 5 mol O2) = (x mol V / 0.725 mol O)

Solving the proportion:

x = (4 mol V / 5 mol O2) * (0.725 mol O)
x = 0.58 mol V

Therefore, approximately 0.58 moles of vanadium atoms (V) are needed to combine with 0.725 moles of oxygen atoms (O) to produce vanadium pentoxide (V2O5).

To find the number of moles of vanadium atoms needed to combine with 0.725 mol of oxygen atoms to form V2O5, we need to examine the balanced chemical equation for the reaction.

The chemical formula for vanadium pentoxide is V2O5, which suggests that there are two moles of vanadium atoms for every mole of V2O5. The balanced chemical equation for the reaction is:

2 V + 5 O2 → V2O5

According to the equation, 2 moles of vanadium atoms react with 5 moles of oxygen molecules (O2) to produce 1 mole of V2O5.

Given that we have 0.725 mol of oxygen atoms, we can use stoichiometry to determine the amount of vanadium atoms needed.

First, we need to determine the moles of oxygen atoms. Since the molar ratio between vanadium atoms (V) and oxygen atoms (O) is 2:5, we can set up the following equation:

0.725 mol O * (2 mol V / 5 mol O) = 0.29 mol V

Therefore, 0.29 moles of vanadium atoms are required to combine with 0.725 mol of oxygen atoms to form vanadium pentoxide (V2O5).