Posted by Anonymous on Sunday, November 25, 2012 at 1:05pm.
y=0.2x^2-1.6x+4.2
= 0.2(x^2 - 8x ) + 4.2
= 0.2(x^2 - 8x + 16 - 16) + 4.2
= 0.2( (x-4)^2 - 16) + 4.2
= 0.2(x-4)^2 - 3.2 + 4.2
= 0.2(x-4)^2 + 1
which is what you got, so you are correct up to that point
Now, the vertex of the parabola is (4,1) which is 1 m above ground. But the pipe starts 4.2 m above the ground and to go down to 1 m above the ground means the change has to be 4.2-1 = 3.2
Make a sketch to see that the pipe would drop 3.2 m from its highest point to its lowest point.
Oh my gosh thanks so much! Makes way more sense now!
Related Questions
Physics - Water is flowing in a pipe with a varying cross-section area, and at ...
physics - a fluid flows through a horizontal pipe of varying cross-section. ...
physics - a fluid flows through a horizontal pipe of varying cross-section. ...
Physics - I can't seem to figure out this problem...what equation would I ...
Calculus - The curved section can be modelled by the parabola y=3x-3/4x^2 Use ...
physics - A venturi meter is a device for measuring the speed of a fluid within ...
physics - A venturi meter is a device for measuring the speed of a fluid within...
math - a cross section of a hollow circular pipe shows that its inner diameter ...
math - A cross section of a hollow circular pipe shows that its inner diameter ...
Physics - A venturi meter is a device for measuring the speed of a fluid within ...
For Further Reading
