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April 18, 2014

April 18, 2014

Posted by **JESS** on Sunday, November 25, 2012 at 1:02pm.

h(x) = arcosh(x^3 + 2).

- maths -
**Reiny**, Sunday, November 25, 2012 at 1:30pmI don't have the derivative of arcosh at the tip of my tongue , and would have to look it up.

I think you can probably do the same.

- maths -
**Steve**, Sunday, November 25, 2012 at 2:19pmjust as d/dx arccos(u) = -1/√(1-u^2) u',

d/dx arccosh(u) = 1/√(x^2-1) u'

so, in this case, you end up with

3x^2/√((x^3+2)^2 - 1)

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