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posted by on .

differentaite w.r to x
h(x) = arcosh(x^3 + 2).

  • maths - ,

    I don't have the derivative of arcosh at the tip of my tongue , and would have to look it up.
    I think you can probably do the same.

  • maths - ,

    just as d/dx arccos(u) = -1/√(1-u^2) u',

    d/dx arccosh(u) = 1/√(x^2-1) u'

    so, in this case, you end up with

    3x^2/√((x^3+2)^2 - 1)

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