Posted by **Eric G** on Saturday, November 24, 2012 at 10:48pm.

a 10 kg mass is attached to one end of a string with a lenght of 5m and whirled in a horizontal circle overheadd at a rate of 1 revolution per second what is tension in the sring

- physics -
**Damon**, Saturday, November 24, 2012 at 11:26pm
It is impossible of course to make that circle exactly horizontal since tan theta = g/Ac

so we must assume that g is small or Ac is much much bigger than g. Let's see:

Ac = v^2/R = w^2 r

where w is omega, radians/second

omega = 2 pi radians/second

so

Ac = (2 pi)^2 (5) = 197 m/s^2

yes, that is much bigger than g so circle is nearly horizontal

F = m Ac = 10*197

= 1970 Newtons in the string

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