Determine the percent by mass of water in your sample of hydrated copper (II) sulfate.

Mass of water = 0.95 g
Mass of anhydrous copper sulfate = 2.19 g
Mass of hydrate copper sulfate = 3.14 g

% H2O = (mass H2O/mass sample)*100 = ?

To determine the percent by mass of water in the sample of hydrated copper (II) sulfate, we need to calculate the ratio of the mass of water to the mass of the entire hydrated compound and then convert it to a percentage.

First, let's find the mass of water in the hydrated copper (II) sulfate:

Mass of water = 0.95 g

Next, we need to find the mass of the anhydrous copper sulfate. The anhydrous compound is the copper (II) sulfate without any water molecules attached. We can calculate this by subtracting the mass of water from the mass of the entire hydrated compound:

Mass of anhydrous copper sulfate = Mass of hydrated copper sulfate - Mass of water
Mass of anhydrous copper sulfate = 3.14 g - 0.95 g
Mass of anhydrous copper sulfate = 2.19 g

Now, we have all the necessary values to calculate the percent by mass of water in the sample:

Percent by mass of water = (Mass of water / Mass of hydrated copper sulfate) x 100
Percent by mass of water = (0.95 g / 3.14 g) x 100
Percent by mass of water ≈ 30.25%

Therefore, the percent by mass of water in the sample of hydrated copper (II) sulfate is approximately 30.25%.