Posted by Anon on Saturday, November 24, 2012 at 7:30pm.
I would make some corrections, one major and two or three minor.
1. Measure out 71g of solution
71 g is not right
2. Put approx. 300.0mL of water into container
3. Add the xxg of solution(solute to the water and mix dissolve the solute completely.
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4. Add more water until 600.0mL of solution is obtained
5. Mix
Isn't the total mass of the Al(NO3)3*9H2O around 247.18 g/mol?
Al = about 27
NO3 = about 62*3 = 186
9H2O = 9*18 = 162
total is about 375 or did I make an error?
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