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Chemistry

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how do I determine the Ka for an acid HX if th epH of a 1.00M solution of HX is 4.5

  • Chemistry - ,

    pH = -log(H^+).
    Substitute and solve for (H^+)

    ......HX ==> H^+ + X^-
    I.....1.0M....0....0
    C......-x.....x.....x
    E....1.0-x.....x....x

    Ka = (H^+)(X^-)/HX
    x= (H^+) from the pH part. Substitute and solve for Ka.

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