Posted by Jill on Saturday, November 24, 2012 at 5:26pm.
pH = -log(H^+).
Substitute and solve for (H^+)
......HX ==> H^+ + X^-
I.....1.0M....0....0
C......-x.....x.....x
E....1.0-x.....x....x
Ka = (H^+)(X^-)/HX
x= (H^+) from the pH part. Substitute and solve for Ka.
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