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a circular ink-blot grows at a rate of 2 sq cm per second. find the rate at which the radius is increasing after (28/11)seconds.

  • maths -

    assuming it had zero area at t=0,

    a = pi r^2
    da/dt = 2pi r dr/dt
    2 = 2pi (28/11) dr/dt
    11/(28pi) = dr/dt

  • maths -

    i tried this way but answer not coming..... :/

    ans is 0.25

  • maths -

    nope. I don't buy it. I think the answer lost a factor of 2 somewhere. 11/(28pi) is 0.125

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