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December 18, 2014

December 18, 2014

Posted by **Abrich** on Saturday, November 24, 2012 at 12:02am.

- Calculus -
**Steve**, Saturday, November 24, 2012 at 12:32amDraw a figure, noting that the trapezoid has 30-cm wide triangles at each end.

When the water is y cm high, its surface is 20+2*30*(y/40) cm across the cross-section. That's 20 + 3y/2.

So, at depth y, the volume

v = (20 + 20+3y/2)/2 * y * 600

= 450y^2 + 12000y

dv/dt = 900y dy/dt + 12000 dy/dt

since .2 m^3 = 200000 cm^3

200000 = 900*25 dy/dt + 12000 dy/dt

dy/dt = 5.80 cm/min

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