For the lewis structure of BCl3, does it have a total of 24 valence electrons? Also does it have a total of 4 bonds? If possible can you draw the lewis structure?

Yes it has 24 electrons. It can't have but three bonds since there are only three atoms hooked to it (the three Cl atoms). I can't draw the Lewis dot structure on this forum but here is a site that shows it. Frankly I don't like the way this site does it but the structure is correct.

But when I take the total number of electrons needed to be "happy" subract the total number of valence electron the result is 4 bonds.

1*8=8
3*8=24
24+8=32

1*3=3 valence electrons
3*7=21 valence electrons
Total valence electron: 24
so... 32-24=8/2=4

By the way, is that correct??

B doesn't obey the octet rule. Look at that structure again at the site and you will see B has only 6 electrons while each Cl has 8.

There can be only three bonds for obvious reasons even if B obeyed the octet rule. That's because there are only three Cl atoms; what else would you add to make the fourth bond?

So would N2 have two bonds then?

I don't think you posted the site.

Excuse me! Here is the site. Sorry about that.

http://biochemhelp.com/lewis-structure-for-bcl3.html

As for nitrogen, it has 10 electrons; the Lewis dot structure is :N:::N:

So for N2, it would be like this?

Step1: 5*2=10 valence electrons
Step2: 8*2=16 electrons total
Step3: 16-10=6 electrons
Step4: 6/2= 3 bond pairs
Step5: 10-6=4/2=2 lone pairs
I am confident that this is correct! Please check.

To determine the number of valence electrons in BCl3, you need to know the electronic configuration of each element.

Boron (B) has an atomic number of 5, meaning it has 5 electrons. However, since it is located in Group 3A of the periodic table, it only has 3 valence electrons.

Chlorine (Cl) is in Group 7A, so it has 7 valence electrons.

To calculate the total number of valence electrons in BCl3, you need to multiply the number of valence electrons for each element by the number of atoms present in the compound:

Boron (B): 3 valence electrons x 1 atom = 3 valence electrons
Chlorine (Cl): 7 valence electrons x 3 atoms = 21 valence electrons

Thus, the total number of valence electrons in BCl3 is 3 + 21 = 24 valence electrons.

The number of bonds in BCl3 can be determined by the octet rule, which states that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration with eight valence electrons (except for hydrogen and helium).

Boron (B) only has 3 valence electrons and needs 5 more to reach the octet, while each Chlorine (Cl) atom has 7 valence electrons and needs 1 more electron to reach the octet.

As a result, each Chlorine (Cl) atom forms a single bond with the Boron (B) atom, and each bond consists of a pair of electrons. BCl3 will, therefore, have a total of 3 bonds.

Below is the Lewis structure for BCl3:

Cl Cl
| |
Cl-B-Cl

I hope this helps!