how many moles are in 243.6 g caco3?
A.7.41 mol caco3
B 2.43 mol caco3
C.102.46 mol caco3
D.88.1 mol cao3
I say A
I don't think so.
mols = grams/molar mass
To determine the number of moles in a given amount of CaCO3, you need to use its molar mass. The molar mass of CaCO3 is calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms.
- The atomic mass of calcium (Ca) is approximately 40.08 g/mol.
- The atomic mass of carbon (C) is approximately 12.01 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.
So, the molar mass of CaCO3 can be calculated as follows:
(40.08 g/mol) + (12.01 g/mol) + (16.00 g/mol x 3) = 100.09 g/mol
Now, you can use the molar mass to determine the number of moles by dividing the given mass (243.6 g) of CaCO3 by its molar mass (100.09 g/mol).
243.6 g CaCO3 / 100.09 g/mol = 2.434 mol CaCO3
Therefore, the answer is B. There are approximately 2.434 mol of CaCO3 in 243.6 g.