Posted by **kawal** on Friday, November 23, 2012 at 4:32pm.

Using digits 2, 3, 5, 6, 7 and 9, how many 3-digit numbers can be formed that are divisible by 5 such that the repetition of digits is not allowed?

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**mystify**, Friday, November 23, 2012 at 4:41pm
herpity derp. If a number is divisible by 5, it must have five or 0 in its ones digit. Thus, five must be in the ones. 6 can be in 1 of 4 places. So can 5 and 4 and 3 and 2. So, the answer is....

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**Reiny**, Friday, November 23, 2012 at 6:48pm
Your number must be in the form

xx5, where the x can only be from 2,3,6,7 or 9

number of 3 digit numbers which are divisible by 5 are

5x4x1 = 20

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