Posted by **confused** on Friday, November 23, 2012 at 3:40pm.

solve the equation in the real number system.

2x^4-23x^3+75x^2-88x+28=0

What are the real solutions of the equations?

please show work. I do not know how to work this at all

- college algebra--need help please!! -
**Damon**, Friday, November 23, 2012 at 4:27pm
x f(x)

1 -6

0 28

-1 216

so there is a zero between zero x=0 AND x = 1

You can iterate and find it

then divide by (x-xo)

However before doing that I would search on Google for a polynomial grapher.

- college algebra--need help please!! -
**Damon**, Friday, November 23, 2012 at 4:32pm
http://mathportal.org/calculators/polynomials-solvers/polynomial-graphing-calculator.php

yields 1/2 , 2 , 7

- college algebra--need help please!! -
**Damon**, Friday, November 23, 2012 at 4:39pm
by the way you can see from the graph that 2 is a double root

If you were clever enough to factor this you would have

(2x-1)(x-2)(x-2)(x-7)

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