Posted by confused on Friday, November 23, 2012 at 3:40pm.
solve the equation in the real number system.
2x^423x^3+75x^288x+28=0
What are the real solutions of the equations?
please show work. I do not know how to work this at all

college algebraneed help please!!  Damon, Friday, November 23, 2012 at 4:27pm
x f(x)
1 6
0 28
1 216
so there is a zero between zero x=0 AND x = 1
You can iterate and find it
then divide by (xxo)
However before doing that I would search on Google for a polynomial grapher.

college algebraneed help please!!  Damon, Friday, November 23, 2012 at 4:32pm
http://mathportal.org/calculators/polynomialssolvers/polynomialgraphingcalculator.php
yields 1/2 , 2 , 7

college algebraneed help please!!  Damon, Friday, November 23, 2012 at 4:39pm
by the way you can see from the graph that 2 is a double root
If you were clever enough to factor this you would have
(2x1)(x2)(x2)(x7)
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