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December 22, 2014

December 22, 2014

Posted by **ladybug** on Friday, November 23, 2012 at 2:55pm.

f(x)=x^5-x^4+9x^3-5x^2-16x+5;[1.3,1.6]

f(x)1.3= ? simplify answer

f(x)1.6= ? "

- college algebra--need help please!! -
**Damon**, Friday, November 23, 2012 at 3:13pm1.3^5 = 3.71293----> 3.71

1.3^4 = 2.8561 ---->-2.86

1.3^3 = 2.197 ----->19.77

1.3^2 = 1.69------->-8.45

-16*1.3 ----------->-20.8

+5 ----------------> +5

add

f(1.3) = -3.63

now do f(1.6)

1.6^5 = 10.48576 ----> 10.5

1.6^4 = 6.5536 ------>-6.55

1.6^3 = 4.096 -------> 36.9

1.6^2 = 2.56 -------->-12.8

1.6*-16 ------------->-25.6

+5------------------->+5

add

f(1.6) = 7.45

ah ha!

somewhere in between there this function which is continuous crossed the x axis at least once to get from -3.63 to + 7.45

Therefore it had at least one zero in there.

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