Posted by ravinder on Thursday, November 22, 2012 at 9:45pm.
y = x^3/(1-x^2)
y' = -x^2(x-3)/(1-x^2)^2
y'' = -2x(x^2+3)/(1-x^2)^3
since the denominator is always positive or 0, y' and y'' are zero when the numerators are zero, and undefined at x=±1.
Now it should be easy to read off the increasing/decreasing/concavity intervals.
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