Posted by ravinder on Thursday, November 22, 2012 at 9:45pm.
Find the first and second derivative of the function
y=f(x)=x^3/(1(x^2))
Use the information about the derivatives to determine any local maxima and minima, regions where the curve iss concave up or down, and any inflection points

math  Steve, Thursday, November 22, 2012 at 11:54pm
y = x^3/(1x^2)
y' = x^2(x3)/(1x^2)^2
y'' = 2x(x^2+3)/(1x^2)^3
since the denominator is always positive or 0, y' and y'' are zero when the numerators are zero, and undefined at x=±1.
Now it should be easy to read off the increasing/decreasing/concavity intervals.
Answer This Question
Related Questions
 Calculus (urgent!!)  Please answer the following questions about the function f...
 Calculus (pleas help!!!)  Please answer the following questions about the ...
 Calculus (pleas help!!!)  Please answer the following questions about the ...
 Calculus  Use the function f to solve the following: a) Local minima, local ...
 increasing decreasing and more  How to analytically find the intervals on which...
 basic calculus  use the first and second derivatives to find the xcoordinates ...
 Calc  1. Find values of a,b,c, and d such that g(x) = a(x^3)+b(x^2)+cx+d has a ...
 Calculus  Suppose that f(x)=3x^3+3x. Find all critical values of f. Then use ...
 Calculus  For f(x)=2(x+5)^3 +7 Find and classify the extreme values, determine ...
 Calculus  For y=(1/4)x^4(2/3)x^3+(1/2)x^23, find the exact intervals on which...
More Related Questions