Posted by mike on Thursday, November 22, 2012 at 9:43pm.
y' = 2ax + b
we want y'(3) = 0, so
6a+b = 0
the line -2x+3 has slope -2, so
we want y'(2) = -2, so
4a+b = -2
and we have (a,b) = (1,-6)
y = x^2 - 6x + c
We know that y(2) = -1, so
-1 = 4 - 12 + c
so, c = 7
y = x^2 - 6x + 7
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