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December 21, 2014

December 21, 2014

Posted by **mike** on Thursday, November 22, 2012 at 9:43pm.

- math -
**Steve**, Friday, November 23, 2012 at 5:16amy' = 2ax + b

we want y'(3) = 0, so

6a+b = 0

the line -2x+3 has slope -2, so

we want y'(2) = -2, so

4a+b = -2

and we have (a,b) = (1,-6)

y = x^2 - 6x + c

We know that y(2) = -1, so

-1 = 4 - 12 + c

so, c = 7

y = x^2 - 6x + 7

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