posted by Q .
A refrigerator does 18kJ of work while moving 115 kJ of thermal enegy from inside the refrigerator. What is its coefficient of performance?
Refrigerators do not do work. Work has to be done UPON them to transfer heat out. I will assume that they meant to say 18 kJ of work IS CONSUMED by the refrigerator.
Refrigerator C.O.P. = Qout/Win
= 115/18 = 6.38