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A refrigerator does 18kJ of work while moving 115 kJ of thermal enegy from inside the refrigerator. What is its coefficient of performance?

  • Physics -

    Refrigerators do not do work. Work has to be done UPON them to transfer heat out. I will assume that they meant to say 18 kJ of work IS CONSUMED by the refrigerator.

    Refrigerator C.O.P. = Qout/Win
    = 115/18 = 6.38

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