Write an equation of a line that passes through (9,-5) and (3,-5). Hint: To answer this question, first find the slope using these 2 points.
m=[-5-(-5)]/(3-9)
m=0
the equation is y=-5
To find the equation of a line that passes through two given points, you need to first find the slope of the line using the formula:
slope (m) = (change in y)/(change in x)
Let's calculate the slope using the given points (9, -5) and (3, -5):
change in y = -5 - (-5) = 0
change in x = 3 - 9 = -6
slope (m) = 0 / -6 = 0
The slope of the line passing through these two points is 0. Now, let's write the equation of the line in point-slope form (y-y₁ = m(x-x₁)), where (x₁, y₁) represents one of the given points:
Using the point (9, -5), we have:
y - (-5) = 0(x - 9)
y + 5 = 0
Thus, the equation of the line passing through (9, -5) and (3, -5) is y + 5 = 0.