Posted by Tara on Thursday, November 22, 2012 at 1:17pm.
How do i find pH of HNO2 i just need a formula to follow cause i cant figure out the equation.
..........HNO2 ==> H^+ + NO2^-
I.........0.045M....0.....0
C.........-x........x.....x
E........0.045-x....x.....x
You know x = (H^+) = 0.0043M because the problem tells you this is the equilibrium concn of H3O^+; therefore,
pH = -log(H^+) = ?
BTW, the problem doesn't tell you the concn of NO2^-; however, you know it is the same as H^+. You also know (HNO2) at equilibrium; it is 0.045-x = ? Finally, the problem doesn't ask for Ka but you can calculate it from
Ka = (H^+)(NO2^-)/(HNO2)
isnt the equilibrium of HNO2 0.0407 because the equilibrium of H+ is 0.0043?
i am confused if no change occured in the reaction according to the chart...
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