Posted by meen on Thursday, November 22, 2012 at 9:42am.
at 10 mph, it is still going east at t=2
so, distance is increasing at 10 mph
at t=3, it turns south. After that, the distance d from P is
d^2 = 30^2 + (10(t-3))^2
since it has only been sailing south for (t-3) hours.
2d dd/dt = 200(t-3)
at t=7, d=50
2*50 dd/dt = 200(4)
dd/dt = 8 mph
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