Calculate the density of atoms along [011] in molybdenum (Mo). Use only the information provided in your class Periodic Table, and express your answer in units of atoms/cm.

2.24*10^7

Name the following crystallographic features below using proper crystallographic notation.

Image One
a)[2ˉ21]
b)[1ˉ12ˉ]
c)[1ˉ1(1/2)]
d)[(1/2)(1/2ˉ)1ˉ]

Image 2
A)(1ˉ02)
B)(21ˉ0)
C)(201)
D)(1ˉ02ˉ)

I know it is NOT d)[(1/2)(1/2ˉ)1ˉ] for Image One and A)(1ˉ02) for image two. One submission left!

Image one is b and Image Two is C

Thank you!

what will be the ans for (011) plane instead of [011]

To calculate the density of atoms along the [011] direction in molybdenum (Mo), we need information from the periodic table and understand the crystal structure of Mo.

1. Atomic mass of Mo:
Look up the atomic mass of molybdenum (Mo) on the periodic table. The atomic mass of Mo is approximately 95.95 g/mol.

2. Crystal structure of Mo:
Molybdenum has a body-centered cubic (BCC) crystal structure. In the BCC structure, there are 2 atoms per unit cell.

3. Lattice constant of Mo:
The lattice constant is the distance between neighboring atoms in a crystal structure. For Mo, the lattice constant (a) is approximately 3.15 Å (angstroms). However, we need to convert this value to cm for consistency. 1 Å = 1 x 10^-8 cm.

4. Determine the direction:
The [011] direction corresponds to the direction in which the values of x, y, and z coordinates of lattice points equal 0, 1, and 1, respectively.

Now let's calculate the atomic density:

Step 1: Calculate the volume of the unit cell
The volume of a BCC unit cell can be calculated using the formula: V = a^3/2
V = (3.15 Å)^3/2 * (1 x 10^-8 cm/Å)^3/2
V ≈ 4.06 x 10^-23 cm^3

Step 2: Calculate the number of unit cells along the [011] direction
The [011] direction corresponds to the direction of the diagonal of the unit cell, which can be calculated using the formula: n = sqrt(h^2 + k^2 + l^2), where h, k, and l are the Miller indices.
For the [011] direction, h = 0, k = 1, and l = 1
n = sqrt(0^2 + 1^2 + 1^2) = sqrt(2)

Step 3: Calculate the number of atoms along the [011] direction
In a BCC structure, there are 2 atoms per unit cell. Therefore, the number of atoms (N) along the [011] direction can be calculated as: N = 2 * n
N = 2 * sqrt(2) ≈ 2.83

Step 4: Calculate the atomic density
The atomic density (ρ) can be calculated as: ρ = N/V
ρ = 2.83 / (4.06 x 10^-23 cm^3)
ρ ≈ 6.97 x 10^22 atoms/cm^3

Therefore, the density of atoms along the [011] direction in molybdenum is approximately 6.97 x 10^22 atoms/cm^3.