precalculus
posted by Ama on .
Find the first six partial sums S1, S2, S3, S4, S5, S6 of the sequence.
1/2, 1/2^2, 1/2^3, 1/2^4'...

an = ( 1 / 2 ) ^ n
a1 = 1 / 2
a2 = 1 / 2 ^ 2 = 1 / 4
a3 = 1 / 2 ^ 3 = 1 / 8
a4 = 1 / 2 ^ 4 = 1 / 16
a5 = 1 / 2 ^ 5 = 1 / 32
a6 = 1 / 2 ^ 6 = 1 / 64
1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 = 63 / 64