Post a New Question

precalculus

posted by on .

Find the first six partial sums S1, S2, S3, S4, S5, S6 of the sequence.

1/2, 1/2^2, 1/2^3, 1/2^4'...

  • precalculus - ,

    an = ( 1 / 2 ) ^ n


    a1 = 1 / 2

    a2 = 1 / 2 ^ 2 = 1 / 4

    a3 = 1 / 2 ^ 3 = 1 / 8

    a4 = 1 / 2 ^ 4 = 1 / 16

    a5 = 1 / 2 ^ 5 = 1 / 32

    a6 = 1 / 2 ^ 6 = 1 / 64


    1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 = 63 / 64

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question