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Homework Help: calc

Posted by sonia on Wednesday, November 21, 2012 at 10:24pm.

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 8−x2. What are the dimensions of such a rectangle with the greatest possible area?
width=
length=

• calc - Steve, Thursday, November 22, 2012 at 7:43pm

  if the rectangle extends from -x to x,
  
  a = 2xy = 2x(8-x^2)
  da/dx = 16 - 6x^2
  a has a max at x = 4/√6
  
  width = 8/√3
  height = 16/3
  

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